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671314124489 is a prime number
BaseRepresentation
bin10011100010011010111…
…00001001111011001001
32101011210000221221021012
421301031130021323021
541444322403440424
61232221503253305
766333534623261
oct11611534117311
92334700857235
10671314124489
1123978035a868
12aa1318aa235
134b3c6416ac8
14246c56167a1
15126e0a0db0e
hex9c4d709ec9

671314124489 has 2 divisors, whose sum is σ = 671314124490. Its totient is φ = 671314124488.

The previous prime is 671314124417. The next prime is 671314124501. The reversal of 671314124489 is 984421413176.

671314124489 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 428075775625 + 243238348864 = 654275^2 + 493192^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-671314124489 is a prime.

It is a super-2 number, since 2×6713141244892 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (671314127489) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 335657062244 + 335657062245.

It is an arithmetic number, because the mean of its divisors is an integer number (335657062245).

Almost surely, 2671314124489 is an apocalyptic number.

It is an amenable number.

671314124489 is a deficient number, since it is larger than the sum of its proper divisors (1).

671314124489 is an equidigital number, since it uses as much as digits as its factorization.

671314124489 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1161216, while the sum is 50.

The spelling of 671314124489 in words is "six hundred seventy-one billion, three hundred fourteen million, one hundred twenty-four thousand, four hundred eighty-nine".