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671540113 is a prime number
BaseRepresentation
bin101000000001101…
…110001110010001
31201210121202212001
4220001232032101
52333403240423
6150345234001
722432665616
oct5001561621
91653552761
10671540113
11315081032
12168a92901
13a918641a
146528a50d
153de4ecad
hex2806e391

671540113 has 2 divisors, whose sum is σ = 671540114. Its totient is φ = 671540112.

The previous prime is 671540041. The next prime is 671540119. The reversal of 671540113 is 311045176.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 614643264 + 56896849 = 24792^2 + 7543^2 .

It is a cyclic number.

It is not a de Polignac number, because 671540113 - 213 = 671531921 is a prime.

It is a super-2 number, since 2×6715401132 = 901932246736105538, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (671540119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 335770056 + 335770057.

It is an arithmetic number, because the mean of its divisors is an integer number (335770057).

Almost surely, 2671540113 is an apocalyptic number.

It is an amenable number.

671540113 is a deficient number, since it is larger than the sum of its proper divisors (1).

671540113 is an equidigital number, since it uses as much as digits as its factorization.

671540113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2520, while the sum is 28.

The square root of 671540113 is about 25914.0910124203. The cubic root of 671540113 is about 875.7039724673.

Adding to 671540113 its reverse (311045176), we get a palindrome (982585289).

The spelling of 671540113 in words is "six hundred seventy-one million, five hundred forty thousand, one hundred thirteen".