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6740740673353 is a prime number
BaseRepresentation
bin110001000010111001101…
…1101000000111101001001
3212212102000210210120222001
41202011303131000331021
51340420014103021403
622200353054231001
71264000560231061
oct142056335007511
925772023716861
106740740673353
112169806419a25
1290a4984b5461
1339b85915c83b
14194379bc63a1
15ba51ea80c1d
hex62173740f49

6740740673353 has 2 divisors, whose sum is σ = 6740740673354. Its totient is φ = 6740740673352.

The previous prime is 6740740673341. The next prime is 6740740673363. The reversal of 6740740673353 is 3533760470476.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6661370007369 + 79370665984 = 2580963^2 + 281728^2 .

It is a cyclic number.

It is not a de Polignac number, because 6740740673353 - 217 = 6740740542281 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 6740740673294 and 6740740673303.

It is not a weakly prime, because it can be changed into another prime (6740740673363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3370370336676 + 3370370336677.

It is an arithmetic number, because the mean of its divisors is an integer number (3370370336677).

Almost surely, 26740740673353 is an apocalyptic number.

It is an amenable number.

6740740673353 is a deficient number, since it is larger than the sum of its proper divisors (1).

6740740673353 is an equidigital number, since it uses as much as digits as its factorization.

6740740673353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26671680, while the sum is 55.

The spelling of 6740740673353 in words is "six trillion, seven hundred forty billion, seven hundred forty million, six hundred seventy-three thousand, three hundred fifty-three".