Base | Representation |
---|---|
bin | 11110111101010011011100… |
… | …11111101111111001110001 |
3 | 22221001002212010122220212201 |
4 | 33132221232133233321301 |
5 | 32410333332334124113 |
6 | 400442103055223201 |
7 | 20224256432511451 |
oct | 1736515637577161 |
9 | 287032763586781 |
10 | 68077085458033 |
11 | 1a767369a7a953 |
12 | 7775966217b01 |
13 | 2bca8458146c2 |
14 | 12b4d3ca31d61 |
15 | 7d0c941c3cdd |
hex | 3dea6e7efe71 |
68077085458033 has 4 divisors (see below), whose sum is σ = 68124132512320. Its totient is φ = 68030038403748.
The previous prime is 68077085457977. The next prime is 68077085458043. The reversal of 68077085458033 is 33085458077086.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 68077085458033 - 229 = 68076548587121 is a prime.
It is a super-3 number, since 3×680770854580333 (a number of 42 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (68077085458043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23523524973 + ... + 23523527866.
It is an arithmetic number, because the mean of its divisors is an integer number (17031033128080).
Almost surely, 268077085458033 is an apocalyptic number.
It is an amenable number.
68077085458033 is a deficient number, since it is larger than the sum of its proper divisors (47047054287).
68077085458033 is a wasteful number, since it uses less digits than its factorization.
68077085458033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47047054286.
The product of its (nonzero) digits is 135475200, while the sum is 64.
The spelling of 68077085458033 in words is "sixty-eight trillion, seventy-seven billion, eighty-five million, four hundred fifty-eight thousand, thirty-three".
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