Base | Representation |
---|---|
bin | 10011110101110001010… |
… | …10000110010100010001 |
3 | 2102011121001020012210201 |
4 | 21322320222012110101 |
5 | 42132111414021213 |
6 | 1241100414255201 |
7 | 100152142561645 |
oct | 11727052062421 |
9 | 2364531205721 |
10 | 681702876433 |
11 | 243121557977 |
12 | b0150ab7501 |
13 | 4c390807bc7 |
14 | 24dcd252c25 |
15 | 12aecaac6dd |
hex | 9eb8a86511 |
681702876433 has 2 divisors, whose sum is σ = 681702876434. Its totient is φ = 681702876432.
The previous prime is 681702876401. The next prime is 681702876457. The reversal of 681702876433 is 334678207186.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 364077078544 + 317625797889 = 603388^2 + 563583^2 .
It is a cyclic number.
It is not a de Polignac number, because 681702876433 - 25 = 681702876401 is a prime.
It is not a weakly prime, because it can be changed into another prime (681702871433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 340851438216 + 340851438217.
It is an arithmetic number, because the mean of its divisors is an integer number (340851438217).
Almost surely, 2681702876433 is an apocalyptic number.
It is an amenable number.
681702876433 is a deficient number, since it is larger than the sum of its proper divisors (1).
681702876433 is an equidigital number, since it uses as much as digits as its factorization.
681702876433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8128512, while the sum is 55.
The spelling of 681702876433 in words is "six hundred eighty-one billion, seven hundred two million, eight hundred seventy-six thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •