Base | Representation |
---|---|
bin | 1001101100110000010111000… |
… | …1110100111110010000010011 |
3 | 10022111122001012011100112121201 |
4 | 2123030011301310332100103 |
5 | 1203430014420142334024 |
6 | 10415341020111132031 |
7 | 263523011200541356 |
oct | 23314056164762023 |
9 | 3274561164315551 |
10 | 682528047621139 |
11 | 18852457945a245 |
12 | 64672612214017 |
13 | 233ac170aa33a5 |
14 | c07876892029d |
15 | 53d91c2c38744 |
hex | 26cc171d3e413 |
682528047621139 has 2 divisors, whose sum is σ = 682528047621140. Its totient is φ = 682528047621138.
The previous prime is 682528047621131. The next prime is 682528047621151. The reversal of 682528047621139 is 931126740825286.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 682528047621139 - 23 = 682528047621131 is a prime.
It is not a weakly prime, because it can be changed into another prime (682528047621131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 341264023810569 + 341264023810570.
It is an arithmetic number, because the mean of its divisors is an integer number (341264023810570).
It is a 2-persistent number, because it is pandigital, and so is 2⋅682528047621139 = 1365056095242278, but 3⋅682528047621139 = 2047584142863417 is not.
Almost surely, 2682528047621139 is an apocalyptic number.
682528047621139 is a deficient number, since it is larger than the sum of its proper divisors (1).
682528047621139 is an equidigital number, since it uses as much as digits as its factorization.
682528047621139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69672960, while the sum is 64.
The spelling of 682528047621139 in words is "six hundred eighty-two trillion, five hundred twenty-eight billion, forty-seven million, six hundred twenty-one thousand, one hundred thirty-nine".
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