Base | Representation |
---|---|
bin | 1001101101010011010111010… |
… | …0010000111010011010001011 |
3 | 10022120202112100022200200022011 |
4 | 2123110311310100322122023 |
5 | 1204014342434240440131 |
6 | 10420521150115040351 |
7 | 263614316651005246 |
oct | 23324656420723213 |
9 | 3276675308620264 |
10 | 683129383921291 |
11 | 1887365aa09392a |
12 | 6474b0745a00b7 |
13 | 23423a94538338 |
14 | c0998d245425d |
15 | 53e9b6a0670b1 |
hex | 26d4d7443a68b |
683129383921291 has 2 divisors, whose sum is σ = 683129383921292. Its totient is φ = 683129383921290.
The previous prime is 683129383921213. The next prime is 683129383921421. The reversal of 683129383921291 is 192129383921386.
683129383921291 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 683129383921291 - 217 = 683129383790219 is a prime.
It is not a weakly prime, because it can be changed into another prime (683129383921991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 341564691960645 + 341564691960646.
It is an arithmetic number, because the mean of its divisors is an integer number (341564691960646).
Almost surely, 2683129383921291 is an apocalyptic number.
683129383921291 is a deficient number, since it is larger than the sum of its proper divisors (1).
683129383921291 is an equidigital number, since it uses as much as digits as its factorization.
683129383921291 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 60466176, while the sum is 67.
The spelling of 683129383921291 in words is "six hundred eighty-three trillion, one hundred twenty-nine billion, three hundred eighty-three million, nine hundred twenty-one thousand, two hundred ninety-one".
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