Base | Representation |
---|---|
bin | 111111101001011010… |
… | …111110111001100011 |
3 | 20112101210000221201112 |
4 | 333221122332321203 |
5 | 2104430203033042 |
6 | 51221213453535 |
7 | 4636355100644 |
oct | 775132767143 |
9 | 215353027645 |
10 | 68340674147 |
11 | 26a8a58aa99 |
12 | 112b31a12ab |
13 | 65a173c735 |
14 | 34444bb6cb |
15 | 1b9eae3982 |
hex | fe96bee63 |
68340674147 has 2 divisors, whose sum is σ = 68340674148. Its totient is φ = 68340674146.
The previous prime is 68340674089. The next prime is 68340674189. The reversal of 68340674147 is 74147604386.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-68340674147 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 68340674095 and 68340674104.
It is not a weakly prime, because it can be changed into another prime (68340674047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34170337073 + 34170337074.
It is an arithmetic number, because the mean of its divisors is an integer number (34170337074).
Almost surely, 268340674147 is an apocalyptic number.
68340674147 is a deficient number, since it is larger than the sum of its proper divisors (1).
68340674147 is an equidigital number, since it uses as much as digits as its factorization.
68340674147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2709504, while the sum is 50.
The spelling of 68340674147 in words is "sixty-eight billion, three hundred forty million, six hundred seventy-four thousand, one hundred forty-seven".
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