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68386813415441 is a prime number
BaseRepresentation
bin11111000110010100010111…
…01110001001000000010001
322222010201022121110101110122
433203022023232021000101
532430422143213243231
6401240245100240025
720255532662640023
oct1743121356110021
9288121277411418
1068386813415441
111a876759372574
1278059a5540015
132c20b05b71011
1412c5d21b20013
157d8d7090577b
hex3e328bb89011

68386813415441 has 2 divisors, whose sum is σ = 68386813415442. Its totient is φ = 68386813415440.

The previous prime is 68386813415387. The next prime is 68386813415449. The reversal of 68386813415441 is 14451431868386.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 65904521785600 + 2482291629841 = 8118160^2 + 1575529^2 .

It is a cyclic number.

It is not a de Polignac number, because 68386813415441 - 214 = 68386813399057 is a prime.

It is a super-3 number, since 3×683868134154413 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (68386813415449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34193406707720 + 34193406707721.

It is an arithmetic number, because the mean of its divisors is an integer number (34193406707721).

Almost surely, 268386813415441 is an apocalyptic number.

It is an amenable number.

68386813415441 is a deficient number, since it is larger than the sum of its proper divisors (1).

68386813415441 is an equidigital number, since it uses as much as digits as its factorization.

68386813415441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 53084160, while the sum is 62.

The spelling of 68386813415441 in words is "sixty-eight trillion, three hundred eighty-six billion, eight hundred thirteen million, four hundred fifteen thousand, four hundred forty-one".