Base | Representation |
---|---|
bin | 11111001110100100010011… |
… | …10110111001111010110011 |
3 | 100000010210220210101201210111 |
4 | 33213102021312321322303 |
5 | 33000043133000000201 |
6 | 402014402150042151 |
7 | 20315155545104530 |
oct | 1747221166717263 |
9 | 300123823351714 |
10 | 68670250000051 |
11 | 1a975986993717 |
12 | 7850907949357 |
13 | 2c41766289bcb |
14 | 12d592d14bd87 |
15 | 7e140ddcab51 |
hex | 3e7489db9eb3 |
68670250000051 has 4 divisors (see below), whose sum is σ = 78480285714352. Its totient is φ = 58860214285752.
The previous prime is 68670250000043. The next prime is 68670250000057. The reversal of 68670250000051 is 15000005207686.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 68670250000051 - 23 = 68670250000043 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 68670249999959 and 68670250000013.
It is not an unprimeable number, because it can be changed into a prime (68670250000057) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4905017857140 + ... + 4905017857153.
It is an arithmetic number, because the mean of its divisors is an integer number (19620071428588).
Almost surely, 268670250000051 is an apocalyptic number.
68670250000051 is a deficient number, since it is larger than the sum of its proper divisors (9810035714301).
68670250000051 is an equidigital number, since it uses as much as digits as its factorization.
68670250000051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9810035714300.
The product of its (nonzero) digits is 100800, while the sum is 40.
The spelling of 68670250000051 in words is "sixty-eight trillion, six hundred seventy billion, two hundred fifty million, fifty-one", and thus it is an aban number.
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