Base | Representation |
---|---|
bin | 100000010111000011… |
… | …0110000011101100001 |
3 | 20122101002100011200001 |
4 | 1000232012300131201 |
5 | 2114310202000113 |
6 | 51531420100001 |
7 | 5010046516432 |
oct | 1005606603541 |
9 | 218332304601 |
10 | 69493000033 |
11 | 27520a94536 |
12 | 11575094601 |
13 | 67263b1382 |
14 | 351355b489 |
15 | 1c1ad637dd |
hex | 102e1b0761 |
69493000033 has 4 divisors (see below), whose sum is σ = 69494312880. Its totient is φ = 69491687188.
The previous prime is 69493000007. The next prime is 69493000037. The reversal of 69493000033 is 33000039496.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 69493000033 - 25 = 69493000001 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 69492999956 and 69493000001.
It is not an unprimeable number, because it can be changed into a prime (69493000037) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 573535 + ... + 684052.
It is an arithmetic number, because the mean of its divisors is an integer number (17373578220).
Almost surely, 269493000033 is an apocalyptic number.
It is an amenable number.
69493000033 is a deficient number, since it is larger than the sum of its proper divisors (1312847).
69493000033 is a wasteful number, since it uses less digits than its factorization.
69493000033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1312846.
The product of its (nonzero) digits is 52488, while the sum is 37.
The spelling of 69493000033 in words is "sixty-nine billion, four hundred ninety-three million, thirty-three", and thus it is an aban number.
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