Base | Representation |
---|---|
bin | 100000010111000101… |
… | …0100100110010100011 |
3 | 20122101011020000110121 |
4 | 1000232022210302203 |
5 | 2114310431011203 |
6 | 51531453341111 |
7 | 5010061155223 |
oct | 1005612446243 |
9 | 218334200417 |
10 | 69494000803 |
11 | 27521608417 |
12 | 11575497797 |
13 | 6726671a46 |
14 | 351373c083 |
15 | 1c1aeb00bd |
hex | 102e2a4ca3 |
69494000803 has 2 divisors, whose sum is σ = 69494000804. Its totient is φ = 69494000802.
The previous prime is 69494000701. The next prime is 69494000809. The reversal of 69494000803 is 30800049496.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 69494000803 - 221 = 69491903651 is a prime.
It is a super-2 number, since 2×694940008032 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 69494000803.
It is not a weakly prime, because it can be changed into another prime (69494000809) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34747000401 + 34747000402.
It is an arithmetic number, because the mean of its divisors is an integer number (34747000402).
Almost surely, 269494000803 is an apocalyptic number.
69494000803 is a deficient number, since it is larger than the sum of its proper divisors (1).
69494000803 is an equidigital number, since it uses as much as digits as its factorization.
69494000803 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 186624, while the sum is 43.
The spelling of 69494000803 in words is "sixty-nine billion, four hundred ninety-four million, eight hundred three", and thus it is an aban number.
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