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697050113 is a prime number
BaseRepresentation
bin101001100011000…
…010010000000001
31210120121210222212
4221203002100001
52411421100423
6153100111505
723162554034
oct5143022001
91716553885
10697050113
11328515081
12175535595
13b15487b6
146880b01b
15412dd578
hex298c2401

697050113 has 2 divisors, whose sum is σ = 697050114. Its totient is φ = 697050112.

The previous prime is 697050077. The next prime is 697050127. The reversal of 697050113 is 311050796.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 658025104 + 39025009 = 25652^2 + 6247^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-697050113 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 697050113.

It is not a weakly prime, because it can be changed into another prime (697050163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 348525056 + 348525057.

It is an arithmetic number, because the mean of its divisors is an integer number (348525057).

Almost surely, 2697050113 is an apocalyptic number.

It is an amenable number.

697050113 is a deficient number, since it is larger than the sum of its proper divisors (1).

697050113 is an equidigital number, since it uses as much as digits as its factorization.

697050113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5670, while the sum is 32.

The square root of 697050113 is about 26401.7066304434. The cubic root of 697050113 is about 886.6549996737.

The spelling of 697050113 in words is "six hundred ninety-seven million, fifty thousand, one hundred thirteen".