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6972056140393 is a prime number
BaseRepresentation
bin110010101110100111011…
…1011011111101001101001
3220200112002120122211101001
41211131032323133221221
51403212232332443033
622454530211355001
71316500023243601
oct145351673375151
926615076584331
106972056140393
112248917a25aa3
129472935b2a61
133b7601235b66
141a1640cdbc01
15c155c376e7d
hex6574eedfa69

6972056140393 has 2 divisors, whose sum is σ = 6972056140394. Its totient is φ = 6972056140392.

The previous prime is 6972056140373. The next prime is 6972056140411. The reversal of 6972056140393 is 3930416502796.

6972056140393 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6909311902249 + 62744238144 = 2628557^2 + 250488^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-6972056140393 is a prime.

It is not a weakly prime, because it can be changed into another prime (6972056140373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3486028070196 + 3486028070197.

It is an arithmetic number, because the mean of its divisors is an integer number (3486028070197).

Almost surely, 26972056140393 is an apocalyptic number.

It is an amenable number.

6972056140393 is a deficient number, since it is larger than the sum of its proper divisors (1).

6972056140393 is an equidigital number, since it uses as much as digits as its factorization.

6972056140393 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7348320, while the sum is 55.

The spelling of 6972056140393 in words is "six trillion, nine hundred seventy-two billion, fifty-six million, one hundred forty thousand, three hundred ninety-three".