Base | Representation |
---|---|
bin | 110010111011110110010… |
… | …1101010111011000110001 |
3 | 220210020110000001220212022 |
4 | 1211313230231113120301 |
5 | 1404143432044243213 |
6 | 22515550052241225 |
7 | 1321524151020635 |
oct | 145675455273061 |
9 | 26706400056768 |
10 | 7000473040433 |
11 | 225997a590654 |
12 | 9508a4310215 |
13 | 3ba1ac631602 |
14 | 1a2b78db0dc5 |
15 | c2171ede308 |
hex | 65decb57631 |
7000473040433 has 4 divisors (see below), whose sum is σ = 7000492907520. Its totient is φ = 7000453173348.
The previous prime is 7000473040391. The next prime is 7000473040453. The reversal of 7000473040433 is 3340403740007.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 7000473040433 - 216 = 7000472974897 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 7000473040393 and 7000473040402.
It is not an unprimeable number, because it can be changed into a prime (7000473040453) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9395273 + ... + 10112966.
It is an arithmetic number, because the mean of its divisors is an integer number (1750123226880).
Almost surely, 27000473040433 is an apocalyptic number.
It is an amenable number.
7000473040433 is a deficient number, since it is larger than the sum of its proper divisors (19867087).
7000473040433 is a wasteful number, since it uses less digits than its factorization.
7000473040433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19867086.
The product of its (nonzero) digits is 84672, while the sum is 35.
The spelling of 7000473040433 in words is "seven trillion, four hundred seventy-three million, forty thousand, four hundred thirty-three".
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