Base | Representation |
---|---|
bin | 10000001001001111111110… |
… | …010100000100100000110011 |
3 | 100022101221200200221020222002 |
4 | 100021033332110010200303 |
5 | 33301313422441410103 |
6 | 411002542512404215 |
7 | 20645616335451536 |
oct | 2011177624044063 |
9 | 308357620836862 |
10 | 71004371044403 |
11 | 2069586a413405 |
12 | 7b6915824666b |
13 | 30808b6737a44 |
14 | 13768b660aa1d |
15 | 831ebed76488 |
hex | 4093fe504833 |
71004371044403 has 2 divisors, whose sum is σ = 71004371044404. Its totient is φ = 71004371044402.
The previous prime is 71004371044379. The next prime is 71004371044417. The reversal of 71004371044403 is 30444017340017.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 71004371044403 - 218 = 71004370782259 is a prime.
It is a super-3 number, since 3×710043710444033 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (71004371041403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35502185522201 + 35502185522202.
It is an arithmetic number, because the mean of its divisors is an integer number (35502185522202).
Almost surely, 271004371044403 is an apocalyptic number.
71004371044403 is a deficient number, since it is larger than the sum of its proper divisors (1).
71004371044403 is an equidigital number, since it uses as much as digits as its factorization.
71004371044403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112896, while the sum is 38.
The spelling of 71004371044403 in words is "seventy-one trillion, four billion, three hundred seventy-one million, forty-four thousand, four hundred three".
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