Base | Representation |
---|---|
bin | 110011110000010101111… |
… | …0001000101100101100011 |
3 | 221012000102010222102101121 |
4 | 1213200223301011211203 |
5 | 1413020313213133103 |
6 | 23043431541113111 |
7 | 1332624505333003 |
oct | 147405361054543 |
9 | 27160363872347 |
10 | 7113200130403 |
11 | 22a276703a824 |
12 | 96a7043b8797 |
13 | 3c7a05b0b503 |
14 | 1a83d043a003 |
15 | c506d71d6bd |
hex | 6782bc45963 |
7113200130403 has 2 divisors, whose sum is σ = 7113200130404. Its totient is φ = 7113200130402.
The previous prime is 7113200130331. The next prime is 7113200130457. The reversal of 7113200130403 is 3040310023117.
7113200130403 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (3040310023117) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 7113200130403 - 217 = 7113199999331 is a prime.
It is not a weakly prime, because it can be changed into another prime (7113200131403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3556600065201 + 3556600065202.
It is an arithmetic number, because the mean of its divisors is an integer number (3556600065202).
Almost surely, 27113200130403 is an apocalyptic number.
7113200130403 is a deficient number, since it is larger than the sum of its proper divisors (1).
7113200130403 is an equidigital number, since it uses as much as digits as its factorization.
7113200130403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 25.
The spelling of 7113200130403 in words is "seven trillion, one hundred thirteen billion, two hundred million, one hundred thirty thousand, four hundred three".
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