Base | Representation |
---|---|
bin | 100001001000001100… |
… | …0101100111111000001 |
3 | 20210121222222112011121 |
4 | 1002100120230333001 |
5 | 2131144304342203 |
6 | 52403201112241 |
7 | 5065650634144 |
oct | 1022030547701 |
9 | 223558875147 |
10 | 71141871553 |
11 | 28197806075 |
12 | 11955328681 |
13 | 6929b989ac |
14 | 362c53405b |
15 | 1cb59b80bd |
hex | 109062cfc1 |
71141871553 has 2 divisors, whose sum is σ = 71141871554. Its totient is φ = 71141871552.
The previous prime is 71141871499. The next prime is 71141871569. The reversal of 71141871553 is 35517814117.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 59454531889 + 11687339664 = 243833^2 + 108108^2 .
It is a cyclic number.
It is not a de Polignac number, because 71141871553 - 213 = 71141863361 is a prime.
It is a super-2 number, since 2×711418715532 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (71141871583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35570935776 + 35570935777.
It is an arithmetic number, because the mean of its divisors is an integer number (35570935777).
Almost surely, 271141871553 is an apocalyptic number.
It is an amenable number.
71141871553 is a deficient number, since it is larger than the sum of its proper divisors (1).
71141871553 is an equidigital number, since it uses as much as digits as its factorization.
71141871553 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 117600, while the sum is 43.
The spelling of 71141871553 in words is "seventy-one billion, one hundred forty-one million, eight hundred seventy-one thousand, five hundred fifty-three".
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