Base | Representation |
---|---|
bin | 100001001001111101… |
… | …1000111100101100001 |
3 | 20210210010122222212112 |
4 | 1002103323013211201 |
5 | 2131310003200212 |
6 | 52413121205105 |
7 | 5100301266344 |
oct | 1022373074541 |
9 | 223703588775 |
10 | 71201225057 |
11 | 28218265256 |
12 | 11971190795 |
13 | 693927a601 |
14 | 363638445b |
15 | 1cbacde422 |
hex | 1093ec7961 |
71201225057 has 2 divisors, whose sum is σ = 71201225058. Its totient is φ = 71201225056.
The previous prime is 71201225033. The next prime is 71201225071. The reversal of 71201225057 is 75052210217.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 59419425121 + 11781799936 = 243761^2 + 108544^2 .
It is an emirp because it is prime and its reverse (75052210217) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-71201225057 is a prime.
It is a super-2 number, since 2×712012250572 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (71201225077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35600612528 + 35600612529.
It is an arithmetic number, because the mean of its divisors is an integer number (35600612529).
Almost surely, 271201225057 is an apocalyptic number.
It is an amenable number.
71201225057 is a deficient number, since it is larger than the sum of its proper divisors (1).
71201225057 is an equidigital number, since it uses as much as digits as its factorization.
71201225057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9800, while the sum is 32.
The spelling of 71201225057 in words is "seventy-one billion, two hundred one million, two hundred twenty-five thousand, fifty-seven".
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