Base | Representation |
---|---|
bin | 110011111001110001000… |
… | …1011110010000111101011 |
3 | 221020221122201201020121002 |
4 | 1213303202023302013223 |
5 | 1413333241223413201 |
6 | 23101020213305215 |
7 | 1334242206246125 |
oct | 147634213620753 |
9 | 27227581636532 |
10 | 7133440451051 |
11 | 2300303191252 |
12 | 97261293520b |
13 | 3c98b0219bc5 |
14 | 1a93905dc215 |
15 | c585560a76b |
hex | 67ce22f21eb |
7133440451051 has 4 divisors (see below), whose sum is σ = 7136741443704. Its totient is φ = 7130139458400.
The previous prime is 7133440451029. The next prime is 7133440451057. The reversal of 7133440451051 is 1501540443317.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 7133440451051 - 210 = 7133440450027 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 7133440450996 and 7133440451014.
It is not an unprimeable number, because it can be changed into a prime (7133440451057) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1650493085 + ... + 1650497406.
It is an arithmetic number, because the mean of its divisors is an integer number (1784185360926).
Almost surely, 27133440451051 is an apocalyptic number.
7133440451051 is a deficient number, since it is larger than the sum of its proper divisors (3300992653).
7133440451051 is a wasteful number, since it uses less digits than its factorization.
7133440451051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3300992652.
The product of its (nonzero) digits is 100800, while the sum is 38.
Adding to 7133440451051 its reverse (1501540443317), we get a palindrome (8634980894368).
The spelling of 7133440451051 in words is "seven trillion, one hundred thirty-three billion, four hundred forty million, four hundred fifty-one thousand, fifty-one".
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