71350995473 has 4 divisors (see below), whose sum is σ = 71437273200. Its totient is φ = 71264717748.

The previous prime is 71350995451. The next prime is 71350995479. The reversal of 71350995473 is 37459905317.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 37459905317 = 29 ⋅1291720873.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-71350995473 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (71350995479) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43137623 + ... + 43139276.

It is an arithmetic number, because the mean of its divisors is an integer number (17859318300).

Almost surely, 2^71350995473 is an apocalyptic number.

It is an amenable number.

71350995473 is a deficient number, since it is larger than the sum of its proper divisors (86277727).

71350995473 is an equidigital number, since it uses as much as digits as its factorization.

71350995473 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 86277726.

The product of its (nonzero) digits is 3572100, while the sum is 53.

The spelling of 71350995473 in words is "seventy-one billion, three hundred fifty million, nine hundred ninety-five thousand, four hundred seventy-three".