Base | Representation |
---|---|
bin | 110100000000111010001… |
… | …1010101011111001100001 |
3 | 221022102020200101201002101 |
4 | 1220001310122223321201 |
5 | 1414111144323430103 |
6 | 23112034214050401 |
7 | 1335324254426551 |
oct | 150016432537141 |
9 | 27272220351071 |
10 | 7148778733153 |
11 | 2306864254652 |
12 | 975593649a01 |
13 | 3cb185b78685 |
14 | 1aa00771d161 |
15 | c5e51e91a1d |
hex | 680746abe61 |
7148778733153 has 2 divisors, whose sum is σ = 7148778733154. Its totient is φ = 7148778733152.
The previous prime is 7148778733133. The next prime is 7148778733163. The reversal of 7148778733153 is 3513378778417.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4058383498849 + 3090395234304 = 2014543^2 + 1757952^2 .
It is a cyclic number.
It is not a de Polignac number, because 7148778733153 - 25 = 7148778733121 is a prime.
It is a super-2 number, since 2×71487787331532 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (7148778733133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3574389366576 + 3574389366577.
It is an arithmetic number, because the mean of its divisors is an integer number (3574389366577).
Almost surely, 27148778733153 is an apocalyptic number.
It is an amenable number.
7148778733153 is a deficient number, since it is larger than the sum of its proper divisors (1).
7148778733153 is an equidigital number, since it uses as much as digits as its factorization.
7148778733153 is an evil number, because the sum of its binary digits is even.
The product of its digits is 82978560, while the sum is 64.
The spelling of 7148778733153 in words is "seven trillion, one hundred forty-eight billion, seven hundred seventy-eight million, seven hundred thirty-three thousand, one hundred fifty-three".
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