Base | Representation |
---|---|
bin | 101010100111010… |
… | …101010100111001 |
3 | 1211211022102120022 |
4 | 222213111110321 |
5 | 2431012012131 |
6 | 154535540225 |
7 | 23501003054 |
oct | 5247252471 |
9 | 1754272508 |
10 | 714954041 |
11 | 33763360a |
12 | 17b52a675 |
13 | b5176b39 |
14 | 6ad4ba9b |
15 | 42b7837b |
hex | 2a9d5539 |
714954041 has 2 divisors, whose sum is σ = 714954042. Its totient is φ = 714954040.
The previous prime is 714954013. The next prime is 714954073. The reversal of 714954041 is 140459417.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 665898025 + 49056016 = 25805^2 + 7004^2 .
It is a cyclic number.
It is not a de Polignac number, because 714954041 - 222 = 710759737 is a prime.
It is a super-2 number, since 2×7149540412 = 1022318561484459362, which contains 22 as substring.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 714953992 and 714954010.
It is not a weakly prime, because it can be changed into another prime (714954341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 357477020 + 357477021.
It is an arithmetic number, because the mean of its divisors is an integer number (357477021).
Almost surely, 2714954041 is an apocalyptic number.
It is an amenable number.
714954041 is a deficient number, since it is larger than the sum of its proper divisors (1).
714954041 is an equidigital number, since it uses as much as digits as its factorization.
714954041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 35.
The square root of 714954041 is about 26738.6245158572. The cubic root of 714954041 is about 894.1822440084.
The spelling of 714954041 in words is "seven hundred fourteen million, nine hundred fifty-four thousand, forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •