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73030451310041 is a prime number
BaseRepresentation
bin10000100110101110111010…
…000110111010110111011001
3100120120122100201101212121112
4100212232322012322313121
534033012331013410131
6415153420504150105
721245163443532521
oct2046567206726731
9316518321355545
1073030451310041
11212a7049956835
12823595a468335
133199985266a54
14140699aac6681
15869a527b002b
hex426bba1badd9

73030451310041 has 2 divisors, whose sum is σ = 73030451310042. Its totient is φ = 73030451310040.

The previous prime is 73030451309989. The next prime is 73030451310071. The reversal of 73030451310041 is 14001315403037.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 41948990054416 + 31081461255625 = 6476804^2 + 5575075^2 .

It is an emirp because it is prime and its reverse (14001315403037) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 73030451310041 - 246 = 2661707132377 is a prime.

It is not a weakly prime, because it can be changed into another prime (73030451310071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36515225655020 + 36515225655021.

It is an arithmetic number, because the mean of its divisors is an integer number (36515225655021).

Almost surely, 273030451310041 is an apocalyptic number.

It is an amenable number.

73030451310041 is a deficient number, since it is larger than the sum of its proper divisors (1).

73030451310041 is an equidigital number, since it uses as much as digits as its factorization.

73030451310041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15120, while the sum is 32.

Adding to 73030451310041 its reverse (14001315403037), we get a palindrome (87031766713078).

The spelling of 73030451310041 in words is "seventy-three trillion, thirty billion, four hundred fifty-one million, three hundred ten thousand, forty-one".