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740147433432019 is a prime number
BaseRepresentation
bin1010100001001010010000000…
…0110110011110001111010011
310121001122101220020011001210121
42220102210000312132033103
51234003033420424311034
611142055011545411111
7311620613245131064
oct25022440066361723
93531571806131717
10740147433432019
111a4919844628878
126b019645a99a97
13259cb7acb309a2
14d0ab4810cc56b
155a87deecae1b4
hex2a12900d9e3d3

740147433432019 has 2 divisors, whose sum is σ = 740147433432020. Its totient is φ = 740147433432018.

The previous prime is 740147433431999. The next prime is 740147433432067. The reversal of 740147433432019 is 910234334741047.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-740147433432019 is a prime.

It is a super-2 number, since 2×7401474334320192 (a number of 31 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (740147433432419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 370073716716009 + 370073716716010.

It is an arithmetic number, because the mean of its divisors is an integer number (370073716716010).

Almost surely, 2740147433432019 is an apocalyptic number.

740147433432019 is a deficient number, since it is larger than the sum of its proper divisors (1).

740147433432019 is an equidigital number, since it uses as much as digits as its factorization.

740147433432019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6096384, while the sum is 52.

The spelling of 740147433432019 in words is "seven hundred forty trillion, one hundred forty-seven billion, four hundred thirty-three million, four hundred thirty-two thousand, nineteen".