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74074092594713 is a prime number
BaseRepresentation
bin10000110101111010110111…
…111110011110011000011001
3100201021102011212121021010022
4100311322313332132120121
534202112220201012323
6421313100211000225
721413451032222621
oct2065726776363031
9321242155537108
1074074092594713
1121669712186842
12838407b899075
133244206abb453
1414412c3155881
15886c855274c8
hex435eb7f9e619

74074092594713 has 2 divisors, whose sum is σ = 74074092594714. Its totient is φ = 74074092594712.

The previous prime is 74074092594659. The next prime is 74074092594727. The reversal of 74074092594713 is 31749529047047.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 59714441710144 + 14359650884569 = 7727512^2 + 3789413^2 .

It is a cyclic number.

It is not a de Polignac number, because 74074092594713 - 210 = 74074092593689 is a prime.

It is a super-3 number, since 3×740740925947133 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (74074092594743) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37037046297356 + 37037046297357.

It is an arithmetic number, because the mean of its divisors is an integer number (37037046297357).

Almost surely, 274074092594713 is an apocalyptic number.

It is an amenable number.

74074092594713 is a deficient number, since it is larger than the sum of its proper divisors (1).

74074092594713 is an equidigital number, since it uses as much as digits as its factorization.

74074092594713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 53343360, while the sum is 62.

The spelling of 74074092594713 in words is "seventy-four trillion, seventy-four billion, ninety-two million, five hundred ninety-four thousand, seven hundred thirteen".