Base | Representation |
---|---|
bin | 100010100000010101… |
… | …1101100110001011001 |
3 | 21002021010112210200012 |
4 | 1011000223230301121 |
5 | 2203224002011213 |
6 | 54012500251305 |
7 | 5232154363016 |
oct | 1050053546131 |
9 | 232233483605 |
10 | 74099641433 |
11 | 29475352394 |
12 | 1243b9a0b35 |
13 | 6cab8b559c |
14 | 382d2a670d |
15 | 1dda4b94a8 |
hex | 1140aecc59 |
74099641433 has 2 divisors, whose sum is σ = 74099641434. Its totient is φ = 74099641432.
The previous prime is 74099641423. The next prime is 74099641439. The reversal of 74099641433 is 33414699047.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 55425872329 + 18673769104 = 235427^2 + 136652^2 .
It is a cyclic number.
It is not a de Polignac number, because 74099641433 - 24 = 74099641417 is a prime.
It is not a weakly prime, because it can be changed into another prime (74099641439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37049820716 + 37049820717.
It is an arithmetic number, because the mean of its divisors is an integer number (37049820717).
Almost surely, 274099641433 is an apocalyptic number.
It is an amenable number.
74099641433 is a deficient number, since it is larger than the sum of its proper divisors (1).
74099641433 is an equidigital number, since it uses as much as digits as its factorization.
74099641433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1959552, while the sum is 50.
The spelling of 74099641433 in words is "seventy-four billion, ninety-nine million, six hundred forty-one thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •