Base | Representation |
---|---|
bin | 1010100100110110001001000… |
… | …0101001000101000000001011 |
3 | 10121120222211021120010002202101 |
4 | 2221031202100221011000023 |
5 | 1240020433100000000021 |
6 | 11154440432115414231 |
7 | 312516450521446402 |
oct | 25115422051050013 |
9 | 3546884246102671 |
10 | 744200000000011 |
11 | 1a61414a1822a65 |
12 | 6b572b422b4377 |
13 | 25c339b3334c09 |
14 | d1ab68797a639 |
15 | 5b0853aad8a91 |
hex | 2a4d890a4500b |
744200000000011 has 2 divisors, whose sum is σ = 744200000000012. Its totient is φ = 744200000000010.
The previous prime is 744199999999957. The next prime is 744200000000021. The reversal of 744200000000011 is 110000000002447.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 744200000000011 - 29 = 744199999999499 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 744199999999898 and 744199999999907.
It is not a weakly prime, because it can be changed into another prime (744200000000021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 372100000000005 + 372100000000006.
It is an arithmetic number, because the mean of its divisors is an integer number (372100000000006).
Almost surely, 2744200000000011 is an apocalyptic number.
744200000000011 is a deficient number, since it is larger than the sum of its proper divisors (1).
744200000000011 is an equidigital number, since it uses as much as digits as its factorization.
744200000000011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 19.
Adding to 744200000000011 its reverse (110000000002447), we get a palindrome (854200000002458).
The spelling of 744200000000011 in words is "seven hundred forty-four trillion, two hundred billion, eleven", and thus it is an aban number.
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