Base | Representation |
---|---|
bin | 101110000010001… |
… | …011111100001011 |
3 | 1222211021011220111 |
4 | 232002023330023 |
5 | 3040203401011 |
6 | 204345335151 |
7 | 25065440524 |
oct | 5602137413 |
9 | 1884234814 |
10 | 772325131 |
11 | 366a59336 |
12 | 1967974b7 |
13 | c4013326 |
14 | 7480384b |
15 | 47c0c121 |
hex | 2e08bf0b |
772325131 has 2 divisors, whose sum is σ = 772325132. Its totient is φ = 772325130.
The previous prime is 772325123. The next prime is 772325143. The reversal of 772325131 is 131523277.
772325131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (131523277) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 772325131 - 23 = 772325123 is a prime.
It is a super-2 number, since 2×7723251312 = 1192972215948334322, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 772325093 and 772325102.
It is not a weakly prime, because it can be changed into another prime (772325731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 386162565 + 386162566.
It is an arithmetic number, because the mean of its divisors is an integer number (386162566).
Almost surely, 2772325131 is an apocalyptic number.
772325131 is a deficient number, since it is larger than the sum of its proper divisors (1).
772325131 is an equidigital number, since it uses as much as digits as its factorization.
772325131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8820, while the sum is 31.
The square root of 772325131 is about 27790.7382233722. The cubic root of 772325131 is about 917.4872877241.
The spelling of 772325131 in words is "seven hundred seventy-two million, three hundred twenty-five thousand, one hundred thirty-one".
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