Base | Representation |
---|---|
bin | 100100110101110100… |
… | …1110001010000010001 |
3 | 21120012200210222202212 |
4 | 1021223221301100101 |
5 | 2244012033214324 |
6 | 100202320121505 |
7 | 5500361564501 |
oct | 1115351612021 |
9 | 246180728685 |
10 | 79115523089 |
11 | 30609717529 |
12 | 133bb766295 |
13 | 75cab14bb5 |
14 | 3b874dda01 |
15 | 20d0a0b70e |
hex | 126ba71411 |
79115523089 has 2 divisors, whose sum is σ = 79115523090. Its totient is φ = 79115523088.
The previous prime is 79115523079. The next prime is 79115523103. The reversal of 79115523089 is 98032551197.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 76551822400 + 2563700689 = 276680^2 + 50633^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-79115523089 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (79115523079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 39557761544 + 39557761545.
It is an arithmetic number, because the mean of its divisors is an integer number (39557761545).
Almost surely, 279115523089 is an apocalyptic number.
It is an amenable number.
79115523089 is a deficient number, since it is larger than the sum of its proper divisors (1).
79115523089 is an equidigital number, since it uses as much as digits as its factorization.
79115523089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 680400, while the sum is 50.
The spelling of 79115523089 in words is "seventy-nine billion, one hundred fifteen million, five hundred twenty-three thousand, eighty-nine".
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