Base | Representation |
---|---|
bin | 10010001100000101010000… |
… | …100010100011000110101011 |
3 | 101111020110101020212010012021 |
4 | 102030011100202203012223 |
5 | 40441114444440400323 |
6 | 442045125515325311 |
7 | 22564312401256321 |
oct | 2214052042430653 |
9 | 344213336763167 |
10 | 79995117121963 |
11 | 2354181416864a |
12 | 8b7b70aa50837 |
13 | 3583679360584 |
14 | 15a7ada29dd11 |
15 | 93accae1a05d |
hex | 48c1508a31ab |
79995117121963 has 2 divisors, whose sum is σ = 79995117121964. Its totient is φ = 79995117121962.
The previous prime is 79995117121939. The next prime is 79995117122087. The reversal of 79995117121963 is 36912171159997.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 79995117121963 - 213 = 79995117113771 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 79995117121892 and 79995117121901.
It is not a weakly prime, because it can be changed into another prime (79995117121163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 39997558560981 + 39997558560982.
It is an arithmetic number, because the mean of its divisors is an integer number (39997558560982).
Almost surely, 279995117121963 is an apocalyptic number.
79995117121963 is a deficient number, since it is larger than the sum of its proper divisors (1).
79995117121963 is an equidigital number, since it uses as much as digits as its factorization.
79995117121963 is an evil number, because the sum of its binary digits is even.
The product of its digits is 57868020, while the sum is 70.
The spelling of 79995117121963 in words is "seventy-nine trillion, nine hundred ninety-five billion, one hundred seventeen million, one hundred twenty-one thousand, nine hundred sixty-three".
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