Base | Representation |
---|---|
bin | 10010010000001111110110… |
… | …011101101101110100101011 |
3 | 101112020211020121201200111102 |
4 | 102100033312131231310223 |
5 | 41010312220342331124 |
6 | 442424430204352015 |
7 | 22624065104540336 |
oct | 2220176635556453 |
9 | 345224217650442 |
10 | 80281368714539 |
11 | 23642156787963 |
12 | 9007097b4560b |
13 | 35a4667a2c855 |
14 | 15b78d34db61d |
15 | 9434815e1aae |
hex | 4903f676dd2b |
80281368714539 has 2 divisors, whose sum is σ = 80281368714540. Its totient is φ = 80281368714538.
The previous prime is 80281368714373. The next prime is 80281368714581. The reversal of 80281368714539 is 93541786318208.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-80281368714539 is a prime.
It is a super-2 number, since 2×802813687145392 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (80281368714839) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40140684357269 + 40140684357270.
It is an arithmetic number, because the mean of its divisors is an integer number (40140684357270).
It is a 2-persistent number, because it is pandigital, and so is 2⋅80281368714539 = 160562737429078, but 3⋅80281368714539 = 240844106143617 is not.
Almost surely, 280281368714539 is an apocalyptic number.
80281368714539 is a deficient number, since it is larger than the sum of its proper divisors (1).
80281368714539 is an equidigital number, since it uses as much as digits as its factorization.
80281368714539 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69672960, while the sum is 65.
The spelling of 80281368714539 in words is "eighty trillion, two hundred eighty-one billion, three hundred sixty-eight million, seven hundred fourteen thousand, five hundred thirty-nine".
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