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80333130121 = 591591357919
BaseRepresentation
bin100101011010000111…
…0100100100110001001
321200100112221211121121
41022310032210212021
52304010240130441
6100523213435241
75542505224306
oct1126416444611
9250315854547
1080333130121
1131083a59732
121369b49bb21
13776316252a
143c610d40ad
152152873dd1
hex12b43a4989

80333130121 has 4 divisors (see below), whose sum is σ = 80334547200. Its totient is φ = 80331713044.

The previous prime is 80333130109. The next prime is 80333130151. The reversal of 80333130121 is 12103133308.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 80333130121 - 217 = 80332999049 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (80333130151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 619801 + ... + 738118.

It is an arithmetic number, because the mean of its divisors is an integer number (20083636800).

Almost surely, 280333130121 is an apocalyptic number.

It is an amenable number.

80333130121 is a deficient number, since it is larger than the sum of its proper divisors (1417079).

80333130121 is a wasteful number, since it uses less digits than its factorization.

80333130121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1417078.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 80333130121 its reverse (12103133308), we get a palindrome (92436263429).

The spelling of 80333130121 in words is "eighty billion, three hundred thirty-three million, one hundred thirty thousand, one hundred twenty-one".

Divisors: 1 59159 1357919 80333130121