Base | Representation |
---|---|
bin | 10010010001111111011010… |
… | …010010100011011000010001 |
3 | 101112200021102201222002020002 |
4 | 102101333122102203120101 |
5 | 41014243031202013132 |
6 | 442555440350455345 |
7 | 22635535401235241 |
oct | 2221773222433021 |
9 | 345607381862202 |
10 | 80401155110417 |
11 | 23688a36008049 |
12 | 9026348204555 |
13 | 35b2a478a873b |
14 | 15bd61831db21 |
15 | 946642952262 |
hex | 491fda4a3611 |
80401155110417 has 2 divisors, whose sum is σ = 80401155110418. Its totient is φ = 80401155110416.
The previous prime is 80401155110363. The next prime is 80401155110431. The reversal of 80401155110417 is 71401155110408.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 65923860661201 + 14477294449216 = 8119351^2 + 3804904^2 .
It is a cyclic number.
It is not a de Polignac number, because 80401155110417 - 228 = 80400886674961 is a prime.
It is not a weakly prime, because it can be changed into another prime (80401155110447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40200577555208 + 40200577555209.
It is an arithmetic number, because the mean of its divisors is an integer number (40200577555209).
Almost surely, 280401155110417 is an apocalyptic number.
It is an amenable number.
80401155110417 is a deficient number, since it is larger than the sum of its proper divisors (1).
80401155110417 is an equidigital number, since it uses as much as digits as its factorization.
80401155110417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 22400, while the sum is 38.
Subtracting from 80401155110417 its reverse (71401155110408), we obtain a palindrome (9000000000009).
The spelling of 80401155110417 in words is "eighty trillion, four hundred one billion, one hundred fifty-five million, one hundred ten thousand, four hundred seventeen".
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