Base | Representation |
---|---|
bin | 111010100000111010000… |
… | …1100011011111101000001 |
3 | 1001110211010202000110121101 |
4 | 1311001310030123331001 |
5 | 2023230234304223033 |
6 | 25034300325254401 |
7 | 1460011301525305 |
oct | 165016414337501 |
9 | 31424122013541 |
10 | 8042128195393 |
11 | 2620713787a46 |
12 | a9a750564401 |
13 | 4644a5857026 |
14 | 1db353755d05 |
15 | de2da6d397d |
hex | 7507431bf41 |
8042128195393 has 2 divisors, whose sum is σ = 8042128195394. Its totient is φ = 8042128195392.
The previous prime is 8042128195373. The next prime is 8042128195489. The reversal of 8042128195393 is 3935918212408.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6719957074944 + 1322171120449 = 2592288^2 + 1149857^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-8042128195393 is a prime.
It is a super-2 number, since 2×80421281953932 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (8042128195373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4021064097696 + 4021064097697.
It is an arithmetic number, because the mean of its divisors is an integer number (4021064097697).
Almost surely, 28042128195393 is an apocalyptic number.
It is an amenable number.
8042128195393 is a deficient number, since it is larger than the sum of its proper divisors (1).
8042128195393 is an equidigital number, since it uses as much as digits as its factorization.
8042128195393 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3732480, while the sum is 55.
The spelling of 8042128195393 in words is "eight trillion, forty-two billion, one hundred twenty-eight million, one hundred ninety-five thousand, three hundred ninety-three".
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