Base | Representation |
---|---|
bin | 10010010010100011000110… |
… | …001100011110000001100011 |
3 | 101112210221100011020010220102 |
4 | 102102203012030132001203 |
5 | 41020410020001130323 |
6 | 443025214505133015 |
7 | 22641363056206241 |
oct | 2222430614360143 |
9 | 345727304203812 |
10 | 80439472676963 |
11 | 236a3209300a14 |
12 | 903186078a16b |
13 | 35b654322233a |
14 | 15c1411299791 |
15 | 9476368a5328 |
hex | 4928c631e063 |
80439472676963 has 2 divisors, whose sum is σ = 80439472676964. Its totient is φ = 80439472676962.
The previous prime is 80439472676921. The next prime is 80439472676971. The reversal of 80439472676963 is 36967627493408.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 80439472676963 - 244 = 62847286632547 is a prime.
It is not a weakly prime, because it can be changed into another prime (80439472676063) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40219736338481 + 40219736338482.
It is an arithmetic number, because the mean of its divisors is an integer number (40219736338482).
Almost surely, 280439472676963 is an apocalyptic number.
80439472676963 is a deficient number, since it is larger than the sum of its proper divisors (1).
80439472676963 is an equidigital number, since it uses as much as digits as its factorization.
80439472676963 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1975228416, while the sum is 74.
The spelling of 80439472676963 in words is "eighty trillion, four hundred thirty-nine billion, four hundred seventy-two million, six hundred seventy-six thousand, nine hundred sixty-three".
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