Base | Representation |
---|---|
bin | 100101011110111110… |
… | …0110000111010000001 |
3 | 21200202220212101020012 |
4 | 1022331330300322001 |
5 | 2304324013442423 |
6 | 100551321354305 |
7 | 5546525462201 |
oct | 1127574607201 |
9 | 250686771205 |
10 | 80496234113 |
11 | 31158031119 |
12 | 13726038995 |
13 | 778ab9ba79 |
14 | 3c78a30401 |
15 | 2161d41078 |
hex | 12bdf30e81 |
80496234113 has 2 divisors, whose sum is σ = 80496234114. Its totient is φ = 80496234112.
The previous prime is 80496234067. The next prime is 80496234121. The reversal of 80496234113 is 31143269408.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 67570363249 + 12925870864 = 259943^2 + 113692^2 .
It is a cyclic number.
It is not a de Polignac number, because 80496234113 - 214 = 80496217729 is a prime.
It is not a weakly prime, because it can be changed into another prime (80496234193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40248117056 + 40248117057.
It is an arithmetic number, because the mean of its divisors is an integer number (40248117057).
Almost surely, 280496234113 is an apocalyptic number.
It is an amenable number.
80496234113 is a deficient number, since it is larger than the sum of its proper divisors (1).
80496234113 is an equidigital number, since it uses as much as digits as its factorization.
80496234113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 124416, while the sum is 41.
The spelling of 80496234113 in words is "eighty billion, four hundred ninety-six million, two hundred thirty-four thousand, one hundred thirteen".
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