Base | Representation |
---|---|
bin | 111010100100110001011… |
… | …0000000010100100110011 |
3 | 1001111121112222210212011200 |
4 | 1311021202300002210303 |
5 | 2023344232410121311 |
6 | 25042151524542243 |
7 | 1460424022320063 |
oct | 165114260024463 |
9 | 31447488725150 |
10 | 8050425473331 |
11 | 262419133a73a |
12 | aa0287251983 |
13 | 4651c8853c47 |
14 | 1db8dd6c53a3 |
15 | de623d51556 |
hex | 75262c02933 |
8050425473331 has 12 divisors (see below), whose sum is σ = 12003501781440. Its totient is φ = 5193822885840.
The previous prime is 8050425473273. The next prime is 8050425473341. The reversal of 8050425473331 is 1333745240508.
8050425473331 is a `hidden beast` number, since 8 + 0 + 5 + 0 + 42 + 547 + 33 + 31 = 666.
It is not a de Polignac number, because 8050425473331 - 213 = 8050425465139 is a prime.
It is a super-2 number, since 2×80504254733312 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (8050425473341) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 14427285516 + ... + 14427286073.
It is an arithmetic number, because the mean of its divisors is an integer number (1000291815120).
Almost surely, 28050425473331 is an apocalyptic number.
8050425473331 is a deficient number, since it is larger than the sum of its proper divisors (3953076308109).
8050425473331 is a wasteful number, since it uses less digits than its factorization.
8050425473331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28854571626 (or 28854571623 counting only the distinct ones).
The product of its (nonzero) digits is 1209600, while the sum is 45.
The spelling of 8050425473331 in words is "eight trillion, fifty billion, four hundred twenty-five million, four hundred seventy-three thousand, three hundred thirty-one".
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