Base | Representation |
---|---|
bin | 111010101001001101100… |
… | …0111101001010011111001 |
3 | 1001112112011112210220021021 |
4 | 1311102123013221103321 |
5 | 2024023300021314433 |
6 | 25050410042542441 |
7 | 1461212231062156 |
oct | 165223307512371 |
9 | 31475145726237 |
10 | 8059961119993 |
11 | 2628234a25162 |
12 | aa20a8807a21 |
13 | 46608828a513 |
14 | 1dc165cd122d |
15 | de9d108822d |
hex | 7549b1e94f9 |
8059961119993 has 2 divisors, whose sum is σ = 8059961119994. Its totient is φ = 8059961119992.
The previous prime is 8059961119957. The next prime is 8059961120023. The reversal of 8059961119993 is 3999111699508.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7744126111929 + 315835008064 = 2782827^2 + 561992^2 .
It is a cyclic number.
It is not a de Polignac number, because 8059961119993 - 225 = 8059927565561 is a prime.
It is not a weakly prime, because it can be changed into another prime (8059961119193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4029980559996 + 4029980559997.
It is an arithmetic number, because the mean of its divisors is an integer number (4029980559997).
Almost surely, 28059961119993 is an apocalyptic number.
It is an amenable number.
8059961119993 is a deficient number, since it is larger than the sum of its proper divisors (1).
8059961119993 is an equidigital number, since it uses as much as digits as its factorization.
8059961119993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42515280, while the sum is 70.
The spelling of 8059961119993 in words is "eight trillion, fifty-nine billion, nine hundred sixty-one million, one hundred nineteen thousand, nine hundred ninety-three".
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