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80671793 is a prime number
BaseRepresentation
bin1001100111011…
…11010000110001
312121210112220012
410303233100301
5131122444133
612001024305
71666461506
oct463572061
9177715805
1080671793
114159aa04
1223025095
13139370b7
14a9dd4ad
157137b48
hex4cef431

80671793 has 2 divisors, whose sum is σ = 80671794. Its totient is φ = 80671792.

The previous prime is 80671771. The next prime is 80671807. The reversal of 80671793 is 39717608.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 80586529 + 85264 = 8977^2 + 292^2 .

It is a cyclic number.

It is not a de Polignac number, because 80671793 - 28 = 80671537 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 80671793.

It is not a weakly prime, because it can be changed into another prime (80671753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40335896 + 40335897.

It is an arithmetic number, because the mean of its divisors is an integer number (40335897).

Almost surely, 280671793 is an apocalyptic number.

It is an amenable number.

80671793 is a deficient number, since it is larger than the sum of its proper divisors (1).

80671793 is an equidigital number, since it uses as much as digits as its factorization.

80671793 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 63504, while the sum is 41.

The square root of 80671793 is about 8981.7477697829. The cubic root of 80671793 is about 432.0896893826.

It can be divided in two parts, 8067 and 1793, that multiplied together give a triangular number (14464131 = T5378).

The spelling of 80671793 in words is "eighty million, six hundred seventy-one thousand, seven hundred ninety-three".