Base | Representation |
---|---|
bin | 10010010110000011010101… |
… | …001110110101110100110110 |
3 | 101120122221210212022012200110 |
4 | 102112003111032311310312 |
5 | 41033331114220004213 |
6 | 443331554135323450 |
7 | 22664645431230666 |
oct | 2226032516656466 |
9 | 346587725265613 |
10 | 80680243125558 |
11 | 23786331a0762a |
12 | 9070456220586 |
13 | 36031640cabbb |
14 | 15ccd31dc01a6 |
15 | 94da2929c5c3 |
hex | 4960d53b5d36 |
80680243125558 has 16 divisors (see below), whose sum is σ = 161377388061120. Its totient is φ = 26890597406856.
The previous prime is 80680243125479. The next prime is 80680243125619. The reversal of 80680243125558 is 85552134208608.
It is a super-3 number, since 3×806802431255583 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 80680243125498 and 80680243125507.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 704180028 + ... + 704294591.
It is an arithmetic number, because the mean of its divisors is an integer number (10086086753820).
Almost surely, 280680243125558 is an apocalyptic number.
80680243125558 is an abundant number, since it is smaller than the sum of its proper divisors (80697144935562).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
80680243125558 is a wasteful number, since it uses less digits than its factorization.
80680243125558 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1408484171.
The product of its (nonzero) digits is 18432000, while the sum is 57.
The spelling of 80680243125558 in words is "eighty trillion, six hundred eighty billion, two hundred forty-three million, one hundred twenty-five thousand, five hundred fifty-eight".
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