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81004021411 = 1131523347059
BaseRepresentation
bin100101101110000110…
…1110100011010100011
321202002022100122110011
41023130031310122203
52311344012141121
6101113541145351
75565232551505
oct1133415643243
9252068318404
1081004021411
1131398727245
12138480bb257
13783c14c521
143cc6251d75
1521916e67e1
hex12dc3746a3

81004021411 has 8 divisors (see below), whose sum is σ = 81727972560. Its totient is φ = 80280195072.

The previous prime is 81004021391. The next prime is 81004021421. The reversal of 81004021411 is 11412040018.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 81004021411 - 215 = 81003988643 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (81004021421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1697800 + ... + 1744858.

It is an arithmetic number, because the mean of its divisors is an integer number (10215996570).

Almost surely, 281004021411 is an apocalyptic number.

81004021411 is a deficient number, since it is larger than the sum of its proper divisors (723951149).

81004021411 is a wasteful number, since it uses less digits than its factorization.

81004021411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62405.

The product of its (nonzero) digits is 256, while the sum is 22.

Adding to 81004021411 its reverse (11412040018), we get a palindrome (92416061429).

The spelling of 81004021411 in words is "eighty-one billion, four million, twenty-one thousand, four hundred eleven".

Divisors: 1 113 15233 47059 1721329 5317667 716849747 81004021411