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810674523509713 is a prime number
BaseRepresentation
bin1011100001010011011101111…
…1000000001001001111010001
310221022100201122101202002020121
42320110313133000021033101
51322224042411004302323
611552054422414510241
7332520205264415032
oct27024673700111721
93838321571662217
10810674523509713
11215340153309755
1276b0a1a1805381
1328a46383214415
1410428bdb946a89
1563ac788812a5d
hex2e14ddf0093d1

810674523509713 has 2 divisors, whose sum is σ = 810674523509714. Its totient is φ = 810674523509712.

The previous prime is 810674523509707. The next prime is 810674523509771. The reversal of 810674523509713 is 317905325476018.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 681651004751809 + 129023518757904 = 26108447^2 + 11358852^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-810674523509713 is a prime.

It is not a weakly prime, because it can be changed into another prime (810674523509113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 405337261754856 + 405337261754857.

It is an arithmetic number, because the mean of its divisors is an integer number (405337261754857).

It is a 1-persistent number, because it is pandigital, but 2⋅810674523509713 = 1621349047019426 is not.

Almost surely, 2810674523509713 is an apocalyptic number.

It is an amenable number.

810674523509713 is a deficient number, since it is larger than the sum of its proper divisors (1).

810674523509713 is an equidigital number, since it uses as much as digits as its factorization.

810674523509713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38102400, while the sum is 61.

The spelling of 810674523509713 in words is "eight hundred ten trillion, six hundred seventy-four billion, five hundred twenty-three million, five hundred nine thousand, seven hundred thirteen".