Base | Representation |
---|---|
bin | 100101110001000010… |
… | …1011110000111011001 |
3 | 21202100011122200111012 |
4 | 1023202011132013121 |
5 | 2312044214334332 |
6 | 101131415543305 |
7 | 5600536562201 |
oct | 1134205360731 |
9 | 252304580435 |
10 | 81102496217 |
11 | 31439276886 |
12 | 1387508ab35 |
13 | 785667aa42 |
14 | 3cd5367401 |
15 | 219a1993b2 |
hex | 12e215e1d9 |
81102496217 has 2 divisors, whose sum is σ = 81102496218. Its totient is φ = 81102496216.
The previous prime is 81102496193. The next prime is 81102496243. The reversal of 81102496217 is 71269420118.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 45495183616 + 35607312601 = 213296^2 + 188699^2 .
It is a cyclic number.
It is not a de Polignac number, because 81102496217 - 210 = 81102495193 is a prime.
It is a super-2 number, since 2×811024962172 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (81102492217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40551248108 + 40551248109.
It is an arithmetic number, because the mean of its divisors is an integer number (40551248109).
Almost surely, 281102496217 is an apocalyptic number.
It is an amenable number.
81102496217 is a deficient number, since it is larger than the sum of its proper divisors (1).
81102496217 is an equidigital number, since it uses as much as digits as its factorization.
81102496217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 41.
The spelling of 81102496217 in words is "eighty-one billion, one hundred two million, four hundred ninety-six thousand, two hundred seventeen".
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