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81116935267 = 436318592009
BaseRepresentation
bin100101110001011110…
…0100011010001100011
321202101011211021010211
41023202330203101203
52312111413412032
6101133053234551
75601103400434
oct1134274432143
9252334737124
1081116935267
1131446439085
1213879a92a57
137859664c64
143cd724548b
15219b59c747
hex12e2f23463

81116935267 has 4 divisors (see below), whose sum is σ = 81135531640. Its totient is φ = 81098338896.

The previous prime is 81116935247. The next prime is 81116935313. The reversal of 81116935267 is 76253961118.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 81116935267 - 231 = 78969451619 is a prime.

It is a super-2 number, since 2×811169352672 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 81116935267.

It is not an unprimeable number, because it can be changed into a prime (81116935247) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9291642 + ... + 9300367.

It is an arithmetic number, because the mean of its divisors is an integer number (20283882910).

Almost surely, 281116935267 is an apocalyptic number.

81116935267 is a deficient number, since it is larger than the sum of its proper divisors (18596373).

81116935267 is a wasteful number, since it uses less digits than its factorization.

81116935267 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18596372.

The product of its digits is 544320, while the sum is 49.

The spelling of 81116935267 in words is "eighty-one billion, one hundred sixteen million, nine hundred thirty-five thousand, two hundred sixty-seven".

Divisors: 1 4363 18592009 81116935267