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8112497 is a prime number
BaseRepresentation
bin11110111100100101110001
3120021011020212
4132330211301
54034044442
6445513505
7125645411
oct36744561
916234225
108112497
114641048
122872895
1318b06c3
141112641
15aa3a82
hex7bc971

8112497 has 2 divisors, whose sum is σ = 8112498. Its totient is φ = 8112496.

The previous prime is 8112493. The next prime is 8112521. The reversal of 8112497 is 7942118.

8112497 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7595536 + 516961 = 2756^2 + 719^2 .

It is a cyclic number.

It is not a de Polignac number, because 8112497 - 22 = 8112493 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (8112493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4056248 + 4056249.

It is an arithmetic number, because the mean of its divisors is an integer number (4056249).

Almost surely, 28112497 is an apocalyptic number.

It is an amenable number.

8112497 is a deficient number, since it is larger than the sum of its proper divisors (1).

8112497 is an equidigital number, since it uses as much as digits as its factorization.

8112497 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4032, while the sum is 32.

The square root of 8112497 is about 2848.2445470851. The cubic root of 8112497 is about 200.9331147141.

The spelling of 8112497 in words is "eight million, one hundred twelve thousand, four hundred ninety-seven".