Base | Representation |
---|---|
bin | 111011000100010111110… |
… | …0010000010100100001001 |
3 | 1001202002201021200121021202 |
4 | 1312020233202002210021 |
5 | 2031002222111020433 |
6 | 25133253335513545 |
7 | 1465345454246312 |
oct | 166105742024411 |
9 | 31662637617252 |
10 | 8118285641993 |
11 | 264aa4466885a |
12 | ab14655288b5 |
13 | 46b7218758b7 |
14 | 200cda043609 |
15 | e129667cee8 |
hex | 7622f882909 |
8118285641993 has 2 divisors, whose sum is σ = 8118285641994. Its totient is φ = 8118285641992.
The previous prime is 8118285641987. The next prime is 8118285642007. The reversal of 8118285641993 is 3991465828118.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8111741964544 + 6543677449 = 2848112^2 + 80893^2 .
It is a cyclic number.
It is not a de Polignac number, because 8118285641993 - 212 = 8118285637897 is a prime.
It is not a weakly prime, because it can be changed into another prime (8118285641933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4059142820996 + 4059142820997.
It is an arithmetic number, because the mean of its divisors is an integer number (4059142820997).
Almost surely, 28118285641993 is an apocalyptic number.
It is an amenable number.
8118285641993 is a deficient number, since it is larger than the sum of its proper divisors (1).
8118285641993 is an equidigital number, since it uses as much as digits as its factorization.
8118285641993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 29859840, while the sum is 65.
The spelling of 8118285641993 in words is "eight trillion, one hundred eighteen billion, two hundred eighty-five million, six hundred forty-one thousand, nine hundred ninety-three".
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