Base | Representation |
---|---|
bin | 10010011101110001011111… |
… | …110100100000100000000001 |
3 | 101122112200101201022021021001 |
4 | 102131301133310200200001 |
5 | 41121024304400423042 |
6 | 444415425445532001 |
7 | 23051201356563106 |
oct | 2235613764404001 |
9 | 348480351267231 |
10 | 81210849232897 |
11 | 2397036725850a |
12 | 9137259114001 |
13 | 36411c5067457 |
14 | 160a8a9d44aad |
15 | 95c731d31bb7 |
hex | 49dc5fd20801 |
81210849232897 has 2 divisors, whose sum is σ = 81210849232898. Its totient is φ = 81210849232896.
The previous prime is 81210849232889. The next prime is 81210849232913. The reversal of 81210849232897 is 79823294801218.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 80042653582336 + 1168195650561 = 8946656^2 + 1080831^2 .
It is a cyclic number.
It is not a de Polignac number, because 81210849232897 - 23 = 81210849232889 is a prime.
It is not a weakly prime, because it can be changed into another prime (81210849232847) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40605424616448 + 40605424616449.
It is an arithmetic number, because the mean of its divisors is an integer number (40605424616449).
Almost surely, 281210849232897 is an apocalyptic number.
It is an amenable number.
81210849232897 is a deficient number, since it is larger than the sum of its proper divisors (1).
81210849232897 is an equidigital number, since it uses as much as digits as its factorization.
81210849232897 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27869184, while the sum is 64.
The spelling of 81210849232897 in words is "eighty-one trillion, two hundred ten billion, eight hundred forty-nine million, two hundred thirty-two thousand, eight hundred ninety-seven".
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