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8132132535433 is a prime number
BaseRepresentation
bin111011001010110100011…
…0111101111110010001001
31001210102110022001200010221
41312111220313233302021
52031214101412113213
625143503342510041
71466345553016114
oct166255067576211
931712408050127
108132132535433
1126558aa8a2845
12ab408a895321
1346cb1a53887a
1420185106357b
15e180711b38d
hex76568defc89

8132132535433 has 2 divisors, whose sum is σ = 8132132535434. Its totient is φ = 8132132535432.

The previous prime is 8132132535389. The next prime is 8132132535523. The reversal of 8132132535433 is 3345352312318.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7964795906809 + 167336628624 = 2822197^2 + 409068^2 .

It is a cyclic number.

It is not a de Polignac number, because 8132132535433 - 29 = 8132132534921 is a prime.

It is a super-2 number, since 2×81321325354332 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 8132132535433.

It is not a weakly prime, because it can be changed into another prime (8132132535133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4066066267716 + 4066066267717.

It is an arithmetic number, because the mean of its divisors is an integer number (4066066267717).

Almost surely, 28132132535433 is an apocalyptic number.

It is an amenable number.

8132132535433 is a deficient number, since it is larger than the sum of its proper divisors (1).

8132132535433 is an equidigital number, since it uses as much as digits as its factorization.

8132132535433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 777600, while the sum is 43.

The spelling of 8132132535433 in words is "eight trillion, one hundred thirty-two billion, one hundred thirty-two million, five hundred thirty-five thousand, four hundred thirty-three".