Search a number
-
+
8139223313323 is a prime number
BaseRepresentation
bin111011001110000111110…
…0000111010101110101011
31001211002202110121111210021
41312130033200322232223
52031323112132011243
625151035122501311
71500016353441004
oct166341740725653
931732673544707
108139223313323
11265890940a163
12ab5529504837
134706aa5a682b
14201d24a901ab
15e1abe8b76ed
hex7670f83abab

8139223313323 has 2 divisors, whose sum is σ = 8139223313324. Its totient is φ = 8139223313322.

The previous prime is 8139223313233. The next prime is 8139223313327. The reversal of 8139223313323 is 3233133229318.

Together with previous prime (8139223313233) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 8139223313323 - 213 = 8139223305131 is a prime.

It is a super-2 number, since 2×81392233133232 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 8139223313323.

It is not a weakly prime, because it can be changed into another prime (8139223313327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4069611656661 + 4069611656662.

It is an arithmetic number, because the mean of its divisors is an integer number (4069611656662).

Almost surely, 28139223313323 is an apocalyptic number.

8139223313323 is a deficient number, since it is larger than the sum of its proper divisors (1).

8139223313323 is an equidigital number, since it uses as much as digits as its factorization.

8139223313323 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 419904, while the sum is 43.

The spelling of 8139223313323 in words is "eight trillion, one hundred thirty-nine billion, two hundred twenty-three million, three hundred thirteen thousand, three hundred twenty-three".